I have a dataframe:
ID time value operation
K1 2020-10-12 07:35:47 K1-0735 create
K1 2020-10-12 07:35:49 K1-0735 upload
K1 2020-10-12 07:35:50
K1 2020-10-12 07:35:55 K1-0735 create
K1 2020-10-12 07:35:58 K1-0735 upload
K1 2020-10-12 07:37:19
KK 2020-10-13 08:11:09 KK-0811 create
KK 2020-10-13 08:11:09 KK-0811 create
KK 2020-10-13 08:11:12 KK-0811 upload
KK 2020-10-13 08:11:15
KK 2020-10-13 08:11:25 KK-0811 create
KK 2020-10-13 08:11:26 KK-0811 upload
As you see column "value" is a join of value of column "ID" and hour and minute from "timestamp" without spaces. I want to add seconds to that value to make it unique within a minute. However they must have same seconds of they are in bundle of "operation" column of values create and upload.
So desired result is:
ID time value operation
K1 2020-10-12 07:35:47 K1-073547 create
K1 2020-10-12 07:35:49 K1-073547 upload
K1 2020-10-12 07:35:50
K1 2020-10-12 07:35:55 K1-073555 create
K1 2020-10-12 07:35:58 K1-073555 upload
K1 2020-10-12 07:37:19
KK 2020-10-13 08:11:09 KK-081109 create
KK 2020-10-13 08:11:09 KK-081109 create
KK 2020-10-13 08:11:12 KK-081109 upload
KK 2020-10-13 08:11:15
KK 2020-10-13 08:11:25 KK-081125 create
KK 2020-10-13 08:11:26 KK-081125 upload
How could i do that transformation with the type of condition?
Code to build dataframe:
ID <- c("K1","K1","K1","K1","K1","K1","KK","KK","KK","KK","KK","KK")
time <- as.Date(c('2020-10-12 07:35:47','2020-10-12 07:35:49','2020-10-12 07:35:50',
'2020-10-12 07:35:55','2020-10-12 07:35:58', '2020-10-12 07:37:19',
'2020-10-13 08:11:09','2020-10-13 08:11:09','2020-10-13 08:11:12',
'2020-10-13 08:11:15','2020-10-13 08:11:25','2020-10-13 08:11:26'))
value <- c("K1-0735","K1-0735",NA,"K1-0735","K1-0735",NA,"KK-0811","KK-0811","KK-0811",
NA,"KK-0811","KK-0811")
operation <- c("create", "upload", NA,"create", "upload", NA,"create","create", "upload",
NA,"create", "upload")
data <- data.frame(ID, time, value,operation)
Read more here: https://stackoverflow.com/questions/65718799/how-to-make-complicated-transformation-of-string-in-column-based-on-value-of-oth
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