# I need Better Code for my Python Arithmatic Formatter project #FreeCodeCamp

I need to improve this code to produce consistent results for a project submission on free code camp, I'm preferably looking for a method to solve these type of problems rather than a straight up solution to this problem.

``````def arithmetic_arranger(equations,ans='False'):
if len(equations)>5: #Checking if more than 5 equations were given
print("Error: Too many problems.")
else:
#Columns
side1=list()
sign=list()
side2=list()
#Initializing Column 1
print(" ",end="")
for i in equations:
isplit=i.split(" ")
side1.append(isplit[0])
sign.append(isplit[1])
side2.append(isplit[2])
for i in side1:
max_len=4
if (len(i)>max_len): #Check for max num of digits
print("Error: Numbers cannot be more than four digits.")
if(len(i)==max_len):
print(i, end="\t\t")
if(len(i)==3):
print(" ",i, end="\t\t")
if(len(i)==2):
print("  ",i, end="\t\t")
if(len(i)==1):
print("   ",i, end="\t\t")
print("\n",end=" ")
a=0;
for i in sign:
print(i, end="")
if (len(side2[a])>max_len): #Check for max num of digits
print("Error: Numbers cannot be more than four digits.")
if(len(side2[a])==max_len):
print(side2[a], end="\t\t")
if(len(side2[a])==3):
print("",side2[a], end="\t\t")
if(len(side2[a])==2):
print(" ",side2[a], end="\t\t")
if(len(side2[a])==1):
print(" ",side2[a], end="\t\t")
a=a+1
print("\n -----     ------      ------      ------")
u=0;
print("   ",end="")
if ans==True:
for i in sign:
if (i=='+'):
result=int(side1[u])+int(side2[u])
if (u==4):
print("",result, end="\t")
if (u==3):
print("",result, end="\t")
if (u==2):
print("",result, end="\t")
if (u==1):
print("",result, end="\t")
if (u==0):
print("", result, end="\t")
if (i=="-"):
result=int(side1[u])-int(side2[u])
if (u==4):
print("",result, end="\t")
if (u==3):
print("  ",result, end="\t")
if (u==2):
print("",result, end="\t")
if (u==1):
print("",result, end="\t")
if (u==0):
print("", result, end="\t")
u=u+1
print("   ", end="")
arithmetic_arranger(["32 + 698", "3801 - 2", "45 + 43", "123 + 49"],True)
#arithmetic_arranger(["32 + 8", "1 - 3801", "9999 + 9999", "523 - 49"], True)
``````

I need it took like this

**[Output] 32 3801 45 123

• 698 - 2 + 43 + 49

``````730     3799        88      172
``````

Repl Closed**

I don't know why this seems so hard, perhaps cause I don't find it interesting. I tried doing it myself but I gave up on account of I don't feel like find a solution to this trivial problem, but if anyone has experience with this I'll be glad if you could share it and some advice to help prevent me from facing similar problems.